4/x^2-x-2+4/x^2-1=3/x^2-3x+2

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Solution for 4/x^2-x-2+4/x^2-1=3/x^2-3x+2 equation: 



4/x^2-x-2+4/x^2-1=3/x^2-3x+2

We move all terms to the left:

4/x^2-x-2+4/x^2-1-(3/x^2-3x+2)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2-3x+2)!=0

x∈R



We add all the numbers together, and all the variables

-1x+4/x^2+4/x^2-(3/x^2-3x+2)-3=0

We get rid of parentheses

-1x+4/x^2+4/x^2-3/x^2+3x-2-3=0

We multiply all the terms by the denominator


-1x*x^2+3x*x^2-2*x^2-3*x^2+4+4-3=0

We add all the numbers together, and all the variables

-5x^2-1x*x^2+3x*x^2+5=0

Wy multiply elements

-5x^2-1x^3+3x^3+5=0

We do not support expression: x^3

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